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                                                                                                         Norton Theorem

                       Example 10


                       Calculate the value of current that flows through 8 Ω by using Norton’s theorem.


















                                                        Figure 3.10(a)



                       Step 1


                       Remove the 8Ω resistor from the circuit and replace the voltage source with a short

                       circuit. Hence, calculate the value of ZN.

















                                                             Figure 3.10(b)








                                                                 ZN  = ([–j4 + (10//j20)] // [j10]) + (-j2)

                                                                   = ([–j4 + (8+j4)] // [j10]) + (-j2)

                                                                   = ([8] // [j10]) + (-j2)

                                                                   = (4.878 + j3.902) + (-j2)

                                                                   = (4.878 + j1.902) Ω

                                     Figure 3.10(c)
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