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Norton Theorem
7) Calculate the current that goes through 10 Ω using Norton’s Theorem.
Figure 3.17
(I10Ω = 0.071 + j0.018 A)
8) Calculate the current that goes through (6 – j9) Ω using Norton’s theorem.
Figure 3.18
(I (6 – j9) Ω = 0.414 + j0.517 A)
9) Determine the current goes through (5+j7) Ω by using Norton’s theorem.
Figure 3.19
(I(5+j7) Ω = 1.1 – j0.157 A)