Page 89 - NETWORK ANALYSIS
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81
                                                                                                         Norton Theorem

                       Step 2


                       Calculate the Norton current source, IN by replacing (5+j10) Ω with a short circuit.







                                                                                     IN







                                                          Figure 3.8(d)


















                                                           Figure 3.8(e)




                            By using Current Divider Rule (CDR),


                                 IN    =    (j5)    x  IT
                                      (j5 − j8)

                                      V
                                 IT  =    =     20       =     20     = (0.561 – j1.248) A
                                      RT  6 + [ (j5)//(−j8) ]  6 +(  j13.33 )

                                                      (j5)
                                       (j5)
                                 IN    =   (j5 − j8)   x  IT =   (j5 − j8)   x (0.561 – j1.248) A = (–0.935 + j2.08) A
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