Page 85 - NETWORK ANALYSIS
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                                                                                                         Norton Theorem


                            By using Ohms Law,

                                     V        (100)
                                 IN =    R T      =    (10 − j10)    =  (5 + j5) A






                       Step 3



                       Draw the Norton equivalent circuit with the impedance (30 – j30) Ω connected to the

                       circuit.















                                             Figure 3.6(e): Norton equivalent circuit



                       Step 4


                       Calculate the current that goes through (30 – j30) Ω.




                        By using Current Divider Rule (CDR),
                                       N             (12 – j4)
                                 iL  =      x IN =                x (5 + j5) A
                                     +   L      (12 – j4) + (30 – j30)
                                    N
                               = (0.685 + j1.507) A



                          The current that flow through the impedance (30 – j30) Ω = (0.685 + j1.507) A
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