Page 87 - NETWORK ANALYSIS
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                                                                                                         Norton Theorem











                                                      Figure 3.7(d)

                                         By using Current Divider Rule (CDR),

                                              IN =    (2−j6)   x 6A  = (−6 − j12) A
                                                 ( 2−j6 +j8 )




                       Step 3



                       Draw the Norton equivalent circuit with the impedance 10Ω connected to the circuit.











                                               Figure 3.7(e): Norton equivalent circuit



                       Step 4



                       Calculate the current that goes through 10Ω.

                          By using Current Divider Rule (CDR),

                                      R N           (4)
                                  iL  =      x IN =       x (−6 − j12) A  = (−1.714 − j3.428) A
                                    R +R  L        (4+10)
                                      N


                          The current that flow through the impedance 10 Ω = (−1.714 − j3.428) A
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