Page 92 - NETWORK ANALYSIS
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84
                                                                                                         Norton Theorem













                                                              Figure 3.9(e)



                                  By using Current Divider Rule (CDR),


                                    IN    =    (4+ j4)    x  2A = (  .        + j0.308) A
                                         (4+ j4+2)





                       Step 3


                       Draw the Norton equivalent circuit with the impedance 5Ω connected to the circuit.














                                                             Figure 3.9(f)


                       Step 4


                       Calculate the current that flows through 5Ω.


                                 Z N            (3.219 – j1.024)
                          IL =         x IN  =                   x (1.538 + j0.308) A
                               Z +Z L         (3.219 – j1.024)  + (5)
                                N

                                           = (0.64 + j8.705) A


                          The current flowing through the impedance 5Ω = (0.64 + j8.705) A
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