Page 80 - NETWORK ANALYSIS
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                                                                                                         Norton Theorem


                                      By using Ohm’s law,
                                              V      (−j15)
                                           IN =    =          = 5 A
                                              R    ( −j3 +j2 )

                       Step 3


                       Draw the Norton equivalent circuit with ZL = (4 + j5) Ω connected to the circuit.















                                              Figure 3.4(h): Norton equivalent circuit



                       Step 4



                       Calculate the current that goes through (4 + j5) Ω.


                         By using Current Divider Rule (CDR),

                                  R N               (0.3 – j0.9)
                             iL=        x IN      =               x (5A)  = (−0.34 −     .       ) A
                                R +R L          (0.3 – j0.9) + (4 + j5)
                                 N


                         The current that flow through the impedance (4 + j5) Ω = (−0.34 −     .       ) A
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