73
Norton Theorem
Example 5
Determine the current goes through (4 + j1) Ω.
Figure 3.5(a)
Step 1
Remove the impedance, ZL = (4 + j1) Ω and replace the voltage source with a short
circuit.
Figure 3.5(b)
ZN = (6 − j5)//(8 − j2) = (6−j5)(8−j2) = (3.657 – j1.886) Ω
( 6−j5 + 8−j2)