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Norton Theorem
Example 3
Find the current flow through the impedance ZL= (2 + j3) Ω using Norton’s
theorem.
Figure 3.3(a)
Step 1
Remove the impedance ZL = (2 + j3) Ω from the circuit and replace the voltage source
with a short circuit.
Figure 3.3(b)
(4−j5)(6−j7)
ZN = (4 − j5)//(6 − j7) = = (2.402 – j2.918) Ω
( 4−j5+ 6−j7)