Page 70 - NETWORK ANALYSIS
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Norton Theorem
Step 2
2) Find the Norton current source, IN by replacing 4Ω resistor with a short circuit.
Figure 3.1(d)
Figure 3.1(e)
IN = V = 10V = 10V = 10V
R T 2 + (5//6) 2 + [(5)(6) ÷(5+6)] 2 +[ 2.727]
= 2.115A
Step 3
Draw the Norton equivalent circuit with the 4Ω resistor connected to the circuit.
= 3 + 0.67
= 3.667Ω
Figure 3.1(f): Norton equivalent circuit
