Page 67 - NETWORK ANALYSIS
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                                                                                                         Norton Theorem

                              Norton’s theorem states that any linear circuit can be simplified to an equivalent

                       circuit consisting of a single current source and parallel resistance that is connected to
                       a load. This circuit is known as Norton equivalent circuit. Applying Norton’s theorem

                       to simplify a circuit that is easier to determine variable loads.




                       Comparison between Thevenin’s and Norton’s theorem


                       Thevenin’s theorem and Norton’s theorem are used to simplify complex circuit into a

                       simple circuit.


                        No           Thevenin’s theorem                      Norton’s theorem

                         1   First, find the Thevenin resistance, Rth  Find  Norton  resistance,  RN  by
                             by removing the load and replaced the  removing  the  load  and  replaced  the

                             voltage source with a short circuit and  voltage source with a short circuit and

                             the  current  source  with  an  open  the  current  source  with  an  open
                             circuit.                              circuit.

                                                              Rth = RN


                         2   Second, calculate the Thevenin        Calculate the Norton current source,
                             voltage, Vth by removing the load.    IN by removing the load and replacing

                                                                   a short circuit.

                         3   Third, draw the Thevenin equivalent   Draw the Norton equivalent circuit.
                             circuit.










                         4   Fourth,  find  the  load  current,  iL  Find  the  load  current,  iL  flowing

                             flowing through the load resistor by  through the load resistor by using:
                             using:                                              R
                                                                            iL=     N   x IN
                                                V                              R +R  L
                                                                                N
                                           iL  =   th
                                              R +R  L
                                               th








                                               = 3 + 0.67
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