Page 61 - NETWORK ANALYSIS
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                                                                                                                       Thevenin Theorem


                             By using Voltage Divider Rule (VDR),


                                   Vth = V (12 +j15) Ω =    (12 +j15)    x  9V = (  .    +      .   ) V
                                                   (12 +j15+3)




                       Step 3


                       Draw the Thevenin equivalent circuit with the (6 – j9) Ω load connected to the circuit.



















                                              Figure 2.10(b): Thevenin equivalent circuit

                       Step 4


                       Calculate the current flows through (6 – j9) Ω.


                          i(10) Ω   =    (8.1+ j0.9)    = (0.414 + j0.517) Amps
                                   (2.7 + j0.3)  + (6 – j9)


                       The current flowing through the load (6 – j9) Ω = (0.414 + j0.517) Amps
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