Page 60 - NETWORK ANALYSIS

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Thevenin Theorem

Step 4

Calculate the current that flows through 10Ω resistor.

i(10) Ω = (2.069 + j5.172) = (0.071 + j0.018) Amps
(34.483 + j61.207) + 10

The current flowing through the resistor (10) Ω = (0.071 + j0.018) Amps

Example 10

Calculate the current that goes through (6 – j9) Ω using Thevenin’s theorem.

Figure 2.10(a)

Step 1

Remove the impedance (6 – j9) Ω from the circuit and replace the voltage source with

a short circuit. Calculate the value of Zth.

Zth = (3) // (12 +j15)

= (3)(12 +j15)
( 3 + 12 +j15)
= (2.7 + j0.3) Ω

Step 2

Calculate the value of Thevenin voltage, Vth by removing the impedance (6 – j9) Ω

from the circuit.