Page 58 - NETWORK ANALYSIS
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                                                                                                                       Thevenin Theorem

                          By using Voltage Divider Rule (VDR);


                                                (20−j30)
                              Vth = V(20-j30) Ω =           x  j36V = (  .      +       .     ) V
                                             (20−j30 + j6 + 8)



                       Step 3

                       Draw the Thevenin equivalent circuit with the 10Ω load connected to the circuit.













                                                Figure 2.8(f): Thevenin equivalent circuit



                       Step 4


                       Calculate the current that flows through the10Ω load.

                                      (9.53 + j33.88 )
                          i(10) Ω   =   (9.118 + j3.529) + (10)   = (0.798 + j1.625) Amps

                       The current flowing through the impedance (10) Ω = (0.798 + j1.625) Amps




                       Example 9


                            Calculate the current that goes through 10Ω using Thevenin’s theorem.

















                                                            Figure 2.9(a)
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