Page 27 - NETWORK ANALYSIS
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Mesh Analysis
Example 10
Solve the current which goes through 12Ω and 6Ω by using Mesh Analysis.
Figure 1.10(a)
Solution
Simplify the circuit using Ohm’s Law;
Figure 1.10(b)
Figure 1.10(c)
Loop i1
By applying Kirchhoff Voltage Law (KVL);
(12 +j10 – j8) i1 – (–j8) i2 = +20<45° V
(12 + j2) i1 + (j8) i2 = 20<45° V ----------------------------- (1)
