Page 29 - NETWORK ANALYSIS
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                                                                                                                                           Mesh Analysis

                       To find ∆ i1

                        (20 < 45°)       j8
                       [                       ]
                          –  j20     (6 –  j10)

                       ∆ i1   = (20 < 45°) (6 –  j10)  – (j8) (–  j20)


                              =     .         –        .       



                          ∆ i1   (    .        –       .      )
                       i1 =     =                    = (0.457 – j0.046) A
                           ∆        (       −         )



                       To find ∆ i2


                        (12  +  j2)  (20 < 45°)
                       [                        ]
                            j8        (–  j20 )


                       ∆ i2   = (12  +  j2) (–  j20)  – (20 < 45°) (j8)

                              =       .         –          .       




                          ∆ i2   (      .        –         .        )
                       i2 =     =                      = (1.723 – j1.071) A
                           ∆         (       −         )



                       i12Ω = i1 = (0.457 – j0.046) A

                       i6Ω = i2 = (1.723 – j1.071) A
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