Page 20 - NETWORK ANALYSIS

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Mesh Analysis

Example 7

Calculate the current that goes through 5Ω, 10Ω and 15Ω.

Figure 1.7

Solution

Loop i1

By applying Kirchhoff Voltage Law (KVL);

(5 + 15 + j20) i1 + (15 + j20) i2 = +10 + 12

(Note: the sources 10V and 12V are positive because it is in the same direction of i1)

(20 + j20) i1 + (15 + j20) i2 = 22 --------------------------- (1)

Loop i2

By applying Kirchhoff Voltage Law (KVL);

(15 + j20 – j10 + 10) i2 + (15 + j20) i1 = +10

(Note: the source 10V is positive because it is in the same direction of i2)

(25 + j10) i2 + (15 + j20) i1 = 10

(15 + j20) i1 + (25 + j10) i2 = 10 --------------------------- (2)