Page 18 - NETWORK ANALYSIS

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Mesh Analysis

Example 6

Referring to Figure 1.6, find the current flows through j10Ω.

Figure 1.6

Solution

Loop i1

By applying Kirchhoff Voltage Law (KVL);

(5 + j10) i1 – (j10) i2 = – 10 <0° --------------------------------- (1)

Loop i2

By applying Kirchhoff Voltage Law (KVL);

(– j15 + j10) i2 – (j10) i1 = + 12 <0°

– (j10) i1 – j5 i2 = 12 <0° --------------------------------- (2)

Converting mesh equations into matrix form;

(5 + j10) (– j10) i1 −10 < 0°
[ ] [ ] = [ ]
(– j10) (– j5) i2 12 < 0°

Solve the equation in each mesh to obtain the values of i1 and i2.