Page 17 - NETWORK ANALYSIS
P. 17
11
Mesh Analysis
To find ∆:
(1 + j2) (j2)
[ ]
(j2) (4 – j)
∆ = (1 + j2) (4 – j) – (j2) (j2) = 10 + j7
To find ∆ i1:
(10 < 45°) (j2)
[ ]
0 (4 – j)
∆ i1 = (10 <45°) (4 – j) – (j2) (0) = 35.355 + j21.213
∆ i1 ( . + . )
i1 = = = 3.369 – j0.237 A
∆ ( + )
To find ∆ i2:
(1 + j2) (10 < 45°)
[ ]
(j2) 0
∆ i2 = (1 + j2) (0) – (10 <45°) (j2) = 14.142 – j14.142
∆ i2 ( . – . )
i2 = = = (0.285 – j1.614) A
∆ ( + )
