Page 12 - NETWORK ANALYSIS

6
Mesh Analysis

Solution

Step 1:

Figure 1.2 shows mesh currents: i1 and i2

Step 2:

Loop i1

By applying Kirchhoff Voltage Law (KVL);

(4 + j4 + 3) i1 − (3) i2 = +20< 0º

(7 + j4) i1 − (3) i2 = +20< 0º --------------------------------- (1)

Loop i2

By applying Kirchhoff Voltage Law (KVL);

(2 + j2 – j2 + 3) i2 − (3) i1 = 0

− (3) i1 + (5) i2 = 0 --------------------------------- (2)

Step 3:

Converting mesh equations into matrix form;

To find ∆:

(7 + j4) −3
[ ]
−3 5