Page 11 - NETWORK ANALYSIS
P. 11

5
                                                                                                                                           Mesh Analysis

                       To find ∆i2:
















                       ∆i2 = (5 x 10) – (12 x 1) =   38

                                38
                       i2 =  ∆ i2  =   = 2.714A
                            ∆   14



                       The current flowing through Resistor R1 (4Ω) is 1.857 Ampere (i1).

                       The current flowing through Resistor R2 (2Ω) is 2.714 Ampere (i2).

                       The current flowing through Resistor R3 (1Ω) is:

                              iR3 = i1 + i2 (The current i1 and i2 flows through R3 are in the same direction)

                              iR3 = 1.857 + 2.714
                              IR3 = 4.571 Ampere






                       Example 2


                       Calculate the value of i1 using Mesh analysis.















                                                          Figure 1.2
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