Page 21 - BASIC CONCEPTUAL OF THERMOFLUID

CHAPTER 2: FLUID APPLICATION

There is concept of manometers can be categorize as shown in Figure Fig. 4 as below:

Simple
Manometer

U-tube
Manometer

IDifferential
Manometer

Fig. 4: Concept of manometers

Example 2.3

Assume that Patm= 101.3 kN/m² water flow in pipe and in mercury in manometer a= 1m h=0.4 m. Calculate the
absolute pressure.

Pa Pb

Figure 2.2: Simple Manometer

Solution:

Datum Line: Pa = Pb
LHL RHL
Pa = ρga + ρgh + Px Pb = Patm

Since, Pa = Pb

ρga + ρgh + Px = Patm
Px = 101300 - (1000 x 9.81 x 1) – (9810 x 13.6 x 0.4)

Px = 38.12 kPa

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