Page 18 - LAPLACE TRANSFORM
P. 18

4
                              2.  f(t) = t
                                      ʆ {f(t)}   = ʆ {t }
                                                   4


                                                   !        4!      1  2  3  4
                                            =          =         =
                                               (  )   +1  (  ) 4+1   (  ) 4+1


                                               24
                                            =
                                                  5



                                                                                        n!
                                                      n
                         5  Power                   t  (   = 1,2,3 … . )
                                                                                      s n+1





                                               A
                                              3  5t
                                         3t
                              3.  f(t) = 5e  + t e
                                                     3t
                                                           3  5t
                                      ʆ {f(t)}   = ʆ {5e  + t e }
                                                               A             n!      1
                                                                        =        .
                                                                            s n+1    −  

                                                                         =     3!    .   1
                                                                                 3+1     −5



                                            = 5 [    1   ] + [      !   ]
                                                  (  −  )     (  −  )   +1




                                            = 5 [    1  ] + [     3!    ]
                                                  (  −3)      (  −5) 3+1


                                            =    5    +   1  2  3
                                               (  −3)   (  −5) 4


                                                 5         6
                                            =         +
                                               (  −3)   (  −5) 4









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