Page 23 - LAPLACE TRANSFORM
P. 23

A     B
                              2)  f(t) = 5e  + t e
                                      3t
                                           3  5t
                                              3t
                              i)     A: ʆ {5 e }   = 5 [   1   ]   (refer to table)
                                                         (s−3)

                                                   =    5
                                                      (s−3)




                                           3
                              ii)    B: ʆ {t }     =     !    (refer to table)
                                                      (  )   +1

                                                   =   3!
                                                      (  ) 3+1

                                                   =  1X2X3
                                                      (s) 3+1

                                                   =   6
                                                       (  ) 4




                                        3  5t
                                     ʆ {t e }      =   6          change s to     s= (s−5)
                                                       (  ) 4


                                                   =       
                                                       (  −  )   





                          ʆ f(t)} = ʆ {5e  + t e } =            +      
                                     3t
                                          3  5t
                                                  (  −  )     (  −  )   




                                  A         B
                                           2t
                                  4 -2t
                       3)  f(t) = 3 t e  + 4 e  cos 7t



                                             4
                              i)     A: ʆ {3 t }   = 3 [     !    ] (refer to table)
                                                          (  )   +1
                                                          4!
                                                   = 3 [     ]
                                                         (  ) 4+1




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