Page 12 - FINAL DBS10012_HEAT TEMPERATURE 20102022 (2) (1)

EXAMPLE 1-1

1) Convert 350 K into Celsius (°C)
Solution:

[°C] = [K] − 273.15
= 350 – 273.15

= 76.85°C

2) Convert 25 °C into °F
Solution:

9
[°F] = [°C] x [K] x ⁄5 + 32
9
= (25) x ⁄5 + 32

= 77°F

3) Convert 300 K into °F
Solution:

First, convert [K] to [°C]

[°C] = [K] − 273.15
= 26.85°C

Then, convert [°C] to [°F]
9
[°F] = [°C] x [K] ⁄5 + 32
9
= (26.85 x ⁄5) + 32

= 80.33°F

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