Page 43 - NETWORK ANALYSIS
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                                                                                                                       Thevenin Theorem

                       Step 1


                       Remove the impedance (15+j20) Ω from the circuit and replace voltage source with a

                       short circuit.















                                                          Figure 2.3(b)






                                                         Zth  = (5 – j10) is parallel to (25 – j30)

                                                          = (5 – j10) // (25 – j30)


                                                            =  (5 – j10)(25 – j30)
                                                            (5 – j10 + 25 – j30)
                                                          = (4.3 – j7.6) Ω




                             Figure 2.3(c)



                       Step 2

                       Calculate the value of Thevenin voltage, Vth by removing the load (15 + j20) Ω from

                       the circuit. There are two different ways to solve for the Thevenin voltage, Vth.














                                                      Figure 2.3(d)
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