Page 84 - LAPLACE TRANSFORM
P. 84
By applying the Laplace transformation method;
10
5I(s) + ⌈I(s) + qo⌉ =
. s
By assuming zero initial condition;
10
5I(s) + ⌈I(s)⌉ =
s
10 10
I(s) [5 + ] =
s s
5s 10 10
I(s) [ + ] =
s s s
5s + 10 10
I(s) [ ] =
s s
10 s
I(s) = x [ ]
s 5s+10
10
I(s) =
5s + 10
10 2
= =
5(s + 2) (s + 2)
By applying the inverse Laplace transformation;
−
( ) = { [ ] }
( + )
= −
When t = 4s;
i(t) = 2e −2(4) = (2)(0.355m) = 0.671mA
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