Page 89 - LAPLACE TRANSFORM
P. 89

By applying the Laplace transform method;

                                          1               10
                       L [sI(s) − i(0)] +   [I(s) + q0] =
                                         CS              S−2



                       By assuming zero initial condition;


                                   1         10
                       L [sI(s)] + [  I(s)] =
                                   CS       S−2
                                 I(s)   10
                       5sI(s) +      =
                                  .        S−2
                                50I(s)  10
                       5sI(s) +       =
                                       S−2

                                        10
                       I(s)[ 5s +   ] =
                                       S−2
                              2
                            5s +50      10
                       I(s) {       } =
                               s       S−2
                       I(s) =   10   x   s
                                        2
                             (s − 2)  (5s  +  50)


                       I(s) =     10s      =        10s       =       2s
                                                       2
                                                                       2
                                     2
                             (s − 2)(5s  +  50)  (s − 2).  5(s  +  10)  (s − 2)(s  +  10)
                       I(s) =      2s      =    A    +   (Bs+C)
                                    2
                                                        2
                             (s − 2)(s  +  10)  (s − 2)    (s  +  10)

                                                   
                                                    2s = A(    +     ) + (Bs + C) (s – 2)





                                                  
                       when s=2            ;2s = A(    +     ) + (Bs + C) (s – 2)


                                                  2
                                                2(2) = A [(2)  + 10]


                                                    4 = A [14]


                                                   
                                                   A =        =
                                                       






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