Page 92 - LAPLACE TRANSFORM
P. 92

SOLUTION



                       By using Kirchhoff’s voltage law;



                       VL + VC =   VS

                        di
                              1
                                 t
                                              -3t
                       L  +  ∫ i(t)dt = 12e
                        dt    C 0

                       By applying the Laplace transformation method;

                                          1               12
                       L [sI(s) − i(0)] +   [I(s) + q0] =
                                         CS              s+3



                       By assuming zero initial condition;

                                   1         12
                       L [sI(s)] + [  I(s)] =
                                   CS       s + 3

                                 I(s)   12
                       4sI(s) +       =
                                50mS   s + 3
                                20I(s)  12
                       4sI(s) +       =
                                       s + 3

                                        12
                       I(s)[ 4s +   ] =
                                       s + 3
                              2
                            4s + 20      12
                       I(s) {        } =
                               s        s + 3
                              2
                            4s + 20      12        s
                       I(s) {        } =      x
                                                  2
                               s        s + 3  (4s  +  20)

                       I(s) =     12s      =        12s      =      3s
                                                       2
                                     2
                                                                      2
                             (s + 3)(4s  +  20)  (s + 3) .4(s  +  5)  (s + 3)(s  +  5)
                       I(s) =     3s      =    A    +   (Bs+C)
                                                       2
                                    2
                             (s + 3)(s  +  5)  (s + 3)    (s  + 5)

                                                        2
                       multiply each side with (    + 3)(   +  5)


                                                    3s = A(    +   ) + (Bs + C) (s + 3)
                                                   




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