Page 79 - LAPLACE TRANSFORM

ℎ ( + 3) = 0

s = −3; = ( + ) + ( )

2 = (−3)

−
=

2 2
A B 3 − 3
I(s) = + = +
s (s + 3) + 3

2 1 2 1
= ( ) − ( )
3 3 ( + 3)

Step 4: Apply the inverse Laplace transform to produce the solution to the differential

equation in the time-domain

( ) = − −

= 0.2 ;

2 2
( ) = − −3 s
3 3
2 2
= − −3(0.2)
3 3

= 0.667 − 0.366

= .

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