Page 81 - LAPLACE TRANSFORM
P. 81
60
I(s) [15 + 3s] =
60 60 60 20
I(s) = = = =
(15 + 3s) (3s + 15) (3(s + 5)) s(s + 5)
Step 3: Solve the frequency-domain algebra expression.
20
I(s) = = +
( + 5) ( + 5)
= ( + ) + ( )
ℎ = 0; = ( + ) + ( )
20 = (0 + 5)
= = 4
ℎ = −5; = ( + ) + ( )
20 = (−5)
= = −
−
A B 4 −4
I(s) = + = +
s (s + 5) ( + 5)
Step 4: Apply the inverse Laplace transform to produce the solution to the original
differential equation described in the time-domain.
68
