Page 21 - FINAL DBS10012_HEAT TEMPERATURE 20102022 (2) (1)
P. 21

EXAMPLE 1-2


                    1)  Calculate the heat quantity needed to raise a temperature of 7 kg water as much
                             o
                            as 30 C. Specific heat capacity of water is 4200 J/kg  C.
                                                                       o

                          Solution:
                                Q =    mc∆T

                                                           o
                                                     o
                                    =   (7kg) (4200J/kg C) (30 C)
                                    =   882 kJ

                                                                                                           o
                                                                                                    o
                    2)  Calculate the heat quantity needed to raise a temperature of 6 kg metal from 10 C to 80 C.

                                                                o
                         Specific heat capacity of water is 0.38 kJ/kg  C.

                          Solution:

                                Q =    mc∆T
                                    =   (6 kg) (0.38kJ/kg C) (80 C – 10 C)
                                                      o
                                                            o
                                                                  o
                                    =   159.6 kJ


                           3)  To a 1 kg sample of wood 40 kJ of heat is added, and its temperature is found to

                                                o
                                         o
                                 rise from 20 C to 44 C. What is the specific heat capacity of the wood?

                                   Solution:

                                       Q      =      mc∆T

                                                                        o
                                                                 o
                                       40 kJ   =     1 kg x c x (44  C – 20 C)

                                      o
                                 24 kg  C (c)    =    40 kJ

                                             c    =    40 kJ

                                                        o
                                                        24 kg  C

                                                               o
                                              =      1.67 kJ/kg C



                                                                              o
                                                                                     o
                           4)   42 kJ heat is used to raise water temperature from 20 C to 30 C. Determine the mass

                                                                  o
                               of the water.  For water, c water = 4.2 kJ/kg C.
                                Solution:
                                       Q      = mc∆T
                                       42000 J = m x 4.2 x (30-20)

                                       m      = 42000       = 1 kg
                                                 42000



                                                          15
   16   17   18   19   20   21   22   23   24   25   26