Page 31 - FINAL DBS10012_HEAT TEMPERATURE 20102022 (2) (1)
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Energy to be removed to reduce the temperature from 0°C to -11°C
Q3 = mcθ = (2) (2100) (0 - (-11)) = 46,200J
Total energy needed = Q1 + Q2 + Q3 = 588,000 + 668,000 = 46,200J = 1,302,200J
Figure 1.10
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