Page 59 - LAPLACE TRANSFORM
P. 59
6 = 10A + B ............................ (2)
6 = 10(0) + B
B = 6
f(t) = + +
( +5) 1 ( +5) 2 ( +5) 3
= + + −
( +5) 1 ( +5) 2 ( +5) 3
= 6 ( 1 ) − 28 ( 1 )
( +5) 2 ( +5) 3
-5t
e }
= 6 t e − 28 { 1 t 3-1 -5t
(3−1)!
= t e − t e
-5t
2 -5t
10 + 4
s
F
3. (s ) =
( − 2 )(s 2 + ) 4
s
10 + 4 +
s
= +
( − 2 )(s 2 + ) 4 ( −2) (s +4)
2
s
10s + 4 = A(s + 4) + (Bs + C) { ( − 2) }
2
48
