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EXERCISE 2

                                                                             3
               0.04  kg  of a  certain  perfect  gas  occupies a  volume  of 0.0072  m at a  pressure  6.76  bar  and a
                                  o
               temperature of 127 C. Calculate the molecular weight of the gas (M). When the gas is allowed to
                                                                        3
               expand until the pressure is 2.12 bar the final volume is 0.065 m . Calculate the final temperature.
               SOLUTION : EXERCISE 2

                m = 0.04 kg

                V1 = 0.072 m 3                  V2 = 0.065 m  3


                P = 6.76 bar = 676 kN/m   2      P = 2.12 bar = 21
                 1
                                                  2
                T1 =127 + 273 = 400 K


                Gas constant


                P V = mRT   1
                 1 1

                    P V     676´ 0
                R =  1 1  =
                    RT

                        1
                R = 0.3




                 Specific Heat Capacity at Constant Volume (Cv)
























                                                               FIGURE 3.4 p - v diagram for
                                                               reversible constant volume process
















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