Page 30 - LAPLACE TRANSFORM
P. 30

SOLUTION

                                                   
                          1)  F(S) =  −       +
                                           −       +  
                                                  6
                                                -1
                                 -1
                          f(t) = ʆ  {F(S)}   = ʆ  { −   1   +    4   }
                                                         −8     +3
                                                 1
                                            = 6 [ ] −   1   + 4 [  1  ]
                                                        −8      +3

                                                     8t
                                            = 6[1] –e + 4e -3t

                                                         -3t
                                                   8t
                                            = 6 – e + 4e










                                                      
                          2)  F(S) =         −        +
                                               
                                        
                                        +       +         

                                                                  7
                                 -1
                                                -1
                          f(t) = ʆ  {F(S)}   = ʆ  {  2    −   3   +   }
                                                           2
                                                   2
                                                     +9      +9     5

                                                                      1
                                            = 2 [      ] −   3   +  7 [ ]
                                                           2
                                                  2
                                                    +3 2     + 3 2      5

                                                                           −1
                                            = 2 Cos 3t − Sin 3t  +  7 [    ]
                                                                     (  −1)!

                                                                         5−1
                                            = 2 Cos 3t − Sin 3t  +  7 [   ]
                                                                     (5−1)!

                                                                      4
                                                                       
                                            = 2 Cos 3t − Sin 3t  +  7 [ ]
                                                                     24

                                                                     4
                                                                      
                                            = 2 Cos 3t − Sin 3t  +  7
                                                                    24














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