Page 30 - LAPLACE TRANSFORM
P. 30
SOLUTION
1) F(S) = − +
− +
6
-1
-1
f(t) = ʆ {F(S)} = ʆ { − 1 + 4 }
−8 +3
1
= 6 [ ] − 1 + 4 [ 1 ]
−8 +3
8t
= 6[1] –e + 4e -3t
-3t
8t
= 6 – e + 4e
2) F(S) = − +
+ +
7
-1
-1
f(t) = ʆ {F(S)} = ʆ { 2 − 3 + }
2
2
+9 +9 5
1
= 2 [ ] − 3 + 7 [ ]
2
2
+3 2 + 3 2 5
−1
= 2 Cos 3t − Sin 3t + 7 [ ]
( −1)!
5−1
= 2 Cos 3t − Sin 3t + 7 [ ]
(5−1)!
4
= 2 Cos 3t − Sin 3t + 7 [ ]
24
4
= 2 Cos 3t − Sin 3t + 7
24
24